To a solution of 10 g lithium bromide (LiBr) in 150 mL water are added 100 mL of sodium bromide c(NaBr) = 0.05 mol/L solution.
What is the concentration of bromide ions c(Br-) and lithium ions c(Li+) in the resulting solution?
Only red cells need to be completed. State results with two significant numbers after the decimal point.